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49r^2=147
We move all terms to the left:
49r^2-(147)=0
a = 49; b = 0; c = -147;
Δ = b2-4ac
Δ = 02-4·49·(-147)
Δ = 28812
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28812}=\sqrt{9604*3}=\sqrt{9604}*\sqrt{3}=98\sqrt{3}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98\sqrt{3}}{2*49}=\frac{0-98\sqrt{3}}{98} =-\frac{98\sqrt{3}}{98} =-\sqrt{3} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98\sqrt{3}}{2*49}=\frac{0+98\sqrt{3}}{98} =\frac{98\sqrt{3}}{98} =\sqrt{3} $
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